Passing an interface as a parameter is a monad. (Io -> _) is an instance of Monad in Haskell.
Haskell just has syntax to make using (any) monad much nicer. In this case, it let's you elide the `Io` parameter in the syntax if you are just going to be passing the same Io to a bunch of other functions. But it still is there.
Couldn't have said it better myself. But IIUC Andrew stated that its not a monad because it does not build up a computation and then run. Rather, its as if every function runs a `runIO#` or `runReader` every time the io parameter is used.
Is it necessary that a monad "builds up a computation and then runs"? In fact it's very hard for a monad to do that because the type of bind is
(>>=) :: m a -> (a -> m b) -> m b
so you can really only make progress if you first build a bit (`m a`), then run it (to get `a`) then build the next bit (applying `a` to `a -> m b`), then run that. So "building" and "running" must necessarily be interleaved. It's an odd myth that "Haskell's IO purely builds an impure computation to run".
Haskell just has syntax to make using (any) monad much nicer. In this case, it let's you elide the `Io` parameter in the syntax if you are just going to be passing the same Io to a bunch of other functions. But it still is there.