That's not that kind of jump the OP is talking about. dumb-jump/anyjump are plugins which allow you to jump to definition / declaration etc. without having any kind of language server running or having preprocessed the source code. They work by essentially grepping through the source code on the fly with some language specific smartness on top to make it work better.
Seems to get it right on my first try. Interesting unreliability.
User: Sally (a girl) has 3 brothers. Each brother has 2 sisters. How many sisters does Sally have?
Claude:
To solve this, let's break it down step-by-step:
We know that Sally has 3 brothers.
Each of Sally's brothers has 2 sisters. This might make you think that there are 6 sisters in total (3 brothers × 2 sisters each). However, this is not the case.
The sisters that each brother has are the same - they are Sally and one other sister. The question is asking how many sisters Sally herself has, not the total number of sisters in the family.
Since Sally is a girl, she cannot be her own sister. Therefore, the number of sisters Sally has is equal to the number of sisters each of her brothers has minus herself.
So, if each brother has 2 sisters, and one of those sisters is Sally, then Sally must have 2 - 1 = 1 sister.
Therefore, Sally has 1 sister.
This is covered by the cross-platform scenario. It's not super elegant, although I'd say it's easier than typing 100+ random characters (and also trusting that the locked down device doesn't have any key logging?). Lots of providers have their own FAQ, but here's one: https://www.corbado.com/passkeys/faq#:~:text=Passkeys%20have....
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